SONG WEN-jING,CAO CHUN-LINGAND ZHAO ZHI-QIANG
(1.Institute of Applied Mathematics,Jilin University of Finance and Economics,Changchun,130117)
(2.School of Mathematics,Jilin University,Changchun,130012)
(3.No.11 High School of Changchun,Changchun,130000)
Existence of Solutions to a p-Laplacian Equation with Integral Initial Condition
SONG WEN-jING1,CAO CHUN-LING2AND ZHAO ZHI-QIANG3
(1.Institute of Applied Mathematics,Jilin University of Finance and Economics,Changchun,130117)
(2.School of Mathematics,Jilin University,Changchun,130012)
(3.No.11 High School of Changchun,Changchun,130000)
Communicated by Gao Wen-jie
In this paper,a class of one-dimension p-Laplacian equation with nonlocal initial value is studied.The existence of solutions to such a problem is obtained by using the topological degree method.
integral initial condition,existence,topological
Boundary value problems with integral boundary conditions in the ordinary differential equations arise in different areas of applied mathematics and physics.For example,heat conduction,chemical engineering,underground water flow,thermo-elasticity and plasma physics can be reduced to nonlocal problems with integral boundary conditions.For boundary-value problems with integral boundary conditions and comments on their importance,we refer the readers to[1]–[4]and the references therein.For more information about the general theory of integral equations and their relation with boundary-value problems,readers may refer to[5]–[7].
In recent years,the existence and multiplicity of positive solutions for nonlocal problems have attracted great attention to many mathematicians.Readers may refer to[8]–[15]and references therein.On the other hand,initial-value problems with integral conditions constitute a very interesting and important class of problems.The integral initial valueproblems to one-dimension p-Laplacian equation are meaningful in mathematics and physics.
The purpose of this paper is to investigate the existence of solutions to the following one-dimension p-Laplacian equation:
with integral initial value
where
The paper is organized as follows.In Section 2,we provide some necessary preliminaries and in Section 3 the main result is stated and proved.
Let I be the real interval[0,1]and C(I)be the Banach space of all continuous functions u:I→R,equipped with the norm
for any u∈C(I).
Consider the following problem:
where
Integrating(2.1)from 0 to t,we obtain
and by using the initial condition(2.3),we have
Integrating the above equality from 0 to t again,we obtain
Let
define an operator K:C(I)→C(I)by
then(2.4)can be rewritten as
Thus x(t)is a solution to(2.1)–(2.3)if and only if it is a solution to(2.5).
Lemma 2.1I−K is a Fredholm operator.
Proof.To prove that I−K is a Fredholm operator,we need only to show that K is completely continuous.
It is easy to see from the definition of K that K is a bounded linear operator from C(I)to C(I).Obviously,dimR(K)=1.So K is a completely continuous operator.This completes the proof.
Lemma 2.2(Alternative Theorem)Suppose that X is a Banach space and A is a completely continuous operator from X to X.Then for any λ/=0,only one of the following statements holds:
(i)For any y∈X,there exists a unique x∈X,such that
(ii)There exists an x∈X,x/=0 such that
Lemma 2.3The problem(2.1)–(2.3)admits a unique solution.
Proof.Since the problem(2.1)–(2.3)is equivalent to the problem(2.5),we need only to show that the problem(2.5)has a unique solution.
By using Lemma 2.1 and alternative theorem,it is sufficient for us to prove that
has only a trivial solution
On the contrary,suppose(2.6)has a nontrivial solution µ,thenµis a constant,and we have
The definition of K and the above equality yield to
which is contradictory to the assumptions
and
Thus we complete the proof.
Throughout this section,we assume that the following conditions hold:
From Lemma 2.3 we know that u(t)is a solution to the problem(1.1)–(1.3)if and only if it is a solution to the following integral equation:
C1(I)denotes the Banach space with the norm
for any u∈C1(I).
define an operator T:C1(I)→C1(I)by
then(3.1)can be rewritten as
In order to prove the existence of solutions to(3.1),we need the following lemmas.
Lemma 3.1T is completely continuous.
Proof.For any ball B1={u∈C1(I);‖u‖1≤R1},set
Then we have for any u∈B1,
This shows that T(B1)is uniformly bounded.
Since f:[0,1]×R×R→R is continuous,it is uniformly continuous on[0,1]×[−R1,R1]×[−R1,R1]and satisfies condition(H2).Thus for any ε>0,there exists a δ>0 such that for all t1,t2∈[0,1],|t1−t2|<δ,we have
where ϕ−1is uniformly continuous,which implies that T(B1)is equicontinuous on[0,1].Therefore,T:C1(I)→C1(I)is completely continuous.This completes the proof of Lemma 3.1.
Theorem 3.1Assume that the conditions(H1)–(H4)hold.Then(1.1)–(1.3)admits at least one solution.
Proof.Lemmas 2.1 and 3.1 imply that the operator K+T is completely continuous on C1(I).It suffices for us to prove the following equation
has at least one solution.
define H:[0,1]×C1[0,1]→C1[0,1]as
and it is clear that H is completely continuous.
Set
Then we have
To apply the Leray-Schauder degree for hσ,we need only to show that there exists a ball BR(θ)in C1[0,1]whose radius R will be fixed later,such that θ/∈hσ(∂BR(θ)).
Choose
Then for any fixed u∈∂BR(θ),there exists a t0∈[0,1]such that
or
If|u(t0)|=R,a direct calculation leads to
From(H4),we have
This implies hσu/=θ,and hence θ/∈hσ(∂BR(θ)).
Similarly,if|u′(t0)|=R,by directly calculating,we have
This implies hσu/=θ,and hence θ/∈hσ(∂BR(θ)).
Since
we know that(3.2)admits a solution u∈BR(θ),which implies that(1.1)–(1.3)also admit a solution in BR(θ).
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34B15,37C25
A
1674-5647(2017)04-0304-07
10.13447/j.1674-5647.2017.04.02
date:May 30,2016.
The NSF(11271154 and 11326103)of China,Research Project(2014164)of the Education of Jilin Province,and the Youth Studies Program(XJ2012006)of Jilin University of Finance and Economics.
E-mail address:swj-78@163.com(Song W J).
Communications in Mathematical Research2017年4期