CHENG LI-HUAAND ZHANG JUN-MIN
(1.School of Science,Xi’an Polytechnic University,Xi’an,710048)
(2.School of Science,Xi’an University of Architecture and Technology,Xi’an,710055)
Communicated by Ji You-qing
A Fixed Point Approach to the Fuzzy Stability of a Mixed Type Functional Equation
CHENG LI-HUA1AND ZHANG JUN-MIN2
(1.School of Science,Xi’an Polytechnic University,Xi’an,710048)
(2.School of Science,Xi’an University of Architecture and Technology,Xi’an,710055)
Communicated by Ji You-qing
Through the paper,a general solution of a mixed type functional equation in fuzzy Banach space is obtained and by using the fixed point method a generalized Hyers-Ulam-Rassias stability of the mixed type functional equation in fuzzy Banach space is proved.
mixed functional equation,Hyers-Ulam stability,Fuzzy Banach space, fixed point
2010 MR subject classification:46S40,47S40,47H10,39B52
Document code:A
Article ID:1674-5647(2016)02-0122-09
The stability problem of functional equation originated from a question of Ulam[1]in 1940, concerning the stability of a group hmomorphisms.Heyers[2]gave a first affirmative partial answers to the question of Ulam for Banach spaces.Heyers theorem was generalized by Aoki[3]for additive mapping and by Rassias[4]for linear mappings by considering an unbounded Cauchy difference.A generalization of the Rassias theorem was obtained by Gˇavruta[5]by replacing the unbounded Cauchy difference by a general control function in the spirit of Rassias’approach.
The functional equation is said to be a quadratic function.
The following cubic functional equation was introduced by Rassias[6]:
The function f(x)=x3satisfies(1.2),which is called cubic functional equation.And he established the general solution and the generalized Hyers-Ulam-Rassias stability for(1.2).
Later,Gordji et al.[7]studied solution and stability of mixed type additive-quadraticcubic functional equation:
Choonkil[8]gave a fixed point approach to the fuzzy stability of an additive-quadraticcubic functional equation:
By using the fixed point methods,the stability problems of several functional equations have been extensively investigated by a number of authors,more reference can be seen in [9]–[10].
In this sequel,we adopt the usual terminology,notations and conventions of the theory in[10].
Definition 1.1[10]Let X be a real linear space.A function N:X×R→[0,1]is said to be fuzzy norm on X,if for all x,y∈X and all a,b∈R,
(1)N(x,a)=0 for a≤0;
(2)x=0 if and only if N(x,a)=1 for a>0;
(4)N(x+y,a+b)≥min{N(x,a),N(x,b)};
(6)for x/=0,is continuous on R.
The pair(X,N)is called a fuzzy normed linear space,where X is a linear space and N is a fuzzy norm on X.In the following,we suppose that N(x,a)is left continuous for every x.A sequence{xn}in X is said to be convergent if there exists an x∈X such thatIn that case,x is called N-convergent,and denoted by.A sequence{xn}in fuzzy normed space(X,N)is called Cauchy sequence if for each ε>0 and δ>0,there exists an n0∈N such that
If each Cauchy sequence is convergent,then the fuzzy norm is said to be complete and the fuzzy normed space is called a fuzzy Banach space.
Let X be a set.A function d:X×X→[0,+∞]is called a generalized metric on X if d satisfies:
(1)d(x,y)=0 if and only if x=y;
(2)d(x,y)=d(y,x)for all x,y∈X;
(3)d(x,z)≤d(x,y)+d(y,z).
Theorem 1.1Let(Ω,d)be a complete generalized metric space,and T:Ω→Ω be a strictly contractive mapping with Lipschitz constant L<1.Then for each given element x∈Ω,either
for all nonnegative integers n,or there exists a positive integer n0∈N,such that
(1)for all n>n0,d(Tnx,Tn+1x)<∞;
(2)for all n>n0,the sequence{Tnx}converges to a fixed point y∗of T;
(3)y∗is the unique fixed point of T in the set∆=
By using fixed point methods,we establish the generalized Hyers-Ulam-Rassias stability of the equation(1.3)in a fuzzy Banach space.Throughout this paper,assume that X is a vector space and(Y,N)is a fuzzy Banach space.
For a given mapping f:X→Y for x,y∈X,we define
We now investigate the generalized Hyers-Ulam-Rassias stability problem of the mixed functional equation(1.3)in a fuzzy Banach space.
Theorem 2.1Let s∈{1,−1},and φ:X×X→[0,∞]be a function such that there exists an L<1 with
Let f be an even mapping satisfying f(0)=0 and
Then a unique quardratic mapping
exists for each x∈X and Q:X→Y satisfies
Proof.Putting x=0 in(2.3),we see that
On the other hand,by replacing x by y in(2.3),we obtain
By two inequalities above,it follows
Let us first prove the case of s=1.
Consider the set
and introduce the generalized metric on S:
It is easy to show that(S,d)is complete,see the proof in[8].Now,we define a map J:S→S such that
Let g,h∈S,and c∈[0,∞]be an arbitrary constant with d(g,h)=c.Then for x∈X and g,h∈S,we obtain
So d(g,h)=c implies that
This means
It follows from(2.7)that
By Theorem 1.1,there exists a mapping Q:X→Y satisfying
(1)Q is a fixed point of J,that is,
Since f is even,Q is even,too,the mapping Q is the unique fixed point of J in the set S.
This implies that Q is a unique mapping satisfying(2.13)such that there exists a c∈(0,∞) satisfying
(2)d(Jnf,Q)→0 as n→∞.This implies
Thus,
By(2.3),
Replacing 2−2nt by t in(2.17),for all x,y∈X,t>0 and all n∈N,we have
Since
we obtain
Thus the mapping Q:X→Y is quadratic,as desired.
By(2.2),for all y∈X,t>0,we have
Then the rest of proof is similar to the proof of the case of s=1,we can obtain the following inequality, in the left hand of(2.20),we get
and we can find the unique fixed point Q of J,which satisfies
Corollary 2.1Let θ>0,and p be a real number with 0<p<2,X be a normed vector space with norm∥·∥.Let f be an even mapping satisfying f(0)=0 and
Then a unique quardratic mapping
exists for each x∈X and Q:X→Y satisfies
Proof.The proof follows from Theorem 2.1 by taking s=1 and φ(x,y):=θ(∥x∥p+∥y∥p) for all x,y∈X,we can choose by L=2p−2and we get the desired result.
Corollary 2.2Let θ>0,p be a real number with p>2,and X be a normed vector space with norm∥·∥.Let f be an even mapping satisfying f(0)=0 and
Then a unique quardratic mapping
exists for each x∈X and Q:X→Y satisfies
Proof.The proof follows from Theorem 2.1 by taking s=−1 and φ(x,y):=θ(∥x∥p+∥y∥p) for all x,y∈X,we can choose by L=22−pand we get the desired result.
Theorem 2.2Let s∈{1,−1}and φ:X×X→[0,∞]be a function such that there exists an L<1 with
Let f be an odd mapping satisfying f(0)=0 and
Then a unique additive mapping
exists for each x∈X and A:X→Y satisfies
Proof.Putting x=0 in(2.3).For all x∈X,one has
Then by replacing x by 2y in(2.3),we obtain
Combining(2.29)and(2.30),we lead to
Putting y:=x and g(x):=f(2x)−8f(x)for all x∈X,we obtain
Let us first prove the case of s=1.
Let the set(S,d)be the generalized metric space defined in the proof of Theorem 2.1, and define a map J:S→S as
Let g,h∈S such that d(g,h)=c.Then for all x∈X,g,h∈S,we obtain
So d(g,h)=c implies that the inequality d(Jg,Jh)≤Lc.This means
It follows from(2.7)that
By Theorem 1.2,there exists a mapping A:X→Y satisfying
(1)A is a fixed point of J,that is,A(2x)=2A(x)for all x∈X.Since f is odd,A is odd,too.The mapping A is the unique fixed point of J in the set S.This implies that A is a unique mapping satisfying(2.13)such that there exists a c∈(0,∞)satisfying
(2)d(Jng,A)→0 as n→∞.This implies
Thus,
By(2.3),we get
Then,for all x,y∈X,t>0 and all n∈N,we have
Since
we obtain
Thus the mapping A:X→Y is additive,as desired.
It follows that
Combining above conclusion,we obtain
The rest of the proof is similar to Theorem 2.1.There exists a mapping A:X→ Y satisfying
Theorem 2.3Let s∈{1,−1},and φ:X×X→[0,∞]be a function such that there exists an L<1 with
Let f be an odd mapping satisfying f(0)=0 and
Then a unique cubic mapping
exists for each x∈X and C:X→Y satisfies
Proof.By(2.31),
Let g(x):=f(2x)−2f(x)for all x∈X.Then we obtain
The rest proof is similar to Theorem 2.1.
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10.13447/j.1674-5647.2016.02.05
date:Dec.8,2014.
The NSF(11101323)of China and the SRP(14JK1300)of Shaanxi Education Office.
E-mail address:chenglihua2002@126.com(Cheng L H).
Communications in Mathematical Research2016年2期