Xiao Min and Li Zhong-ping
(College of Mathematic and Information, China West Normal University, Nanchong,Sichuan, 637002)
Communicated by Wang Chun-peng
Abstract: This paper is devoted to dealing with the parabolic-elliptic-elliptic attraction-repulsion chemotaxis system. We aim to understand the competition among the repulsion, the attraction, the nonlinear productions and give conditions of global existence and blow-up for the two-dimensional attraction-repulsion chemotaxis system.Key words: chemotaxis; attraction-repulsion; global boundedness; nonradial solution; blow-up
Chemotaxis is a phenomenon which describes the movement of cells in response to the concentration gradient of the chemical produced by cells themselves. The famous chemotaxis model was first proposed by Keller and Segel[1]in 1970. The Keller-Segel model can be read as follows:
where u = u(x, t) denotes the density of cells, v = v(x, t) represents the concentration of the chemoattractant. The function f : [0, ∞) −→R is smooth, χ is the parameter referred as chemosensitivity. The system (1.1) with τ = 0 or τ = 1 has been studied extensively in the past four decades. For instance, when D(u) ≡1, τ = 0 andΩ⊂R2is a bounded domain, the solution to (1.1) is global bounded provided that f(u) = µu(1 −u) with µ > 0(see [2]).
In order to better understand the parabolic-elliptic-elliptic attraction-repulsion chemotaxis system, let us mention previous contributions as follows:
When n = 1, the main results in [3] showed that the (1.2) admits a unique global solution. Nagai[4]found that there exists the critical mass mc=which determines the behavior of the solution when n = 2. Precisely, if the initial mass(x)dx ≤mc, the solution of system (1.2) is global and bounded, whereas the finite time blow-up happens when. In addition, the blow-up may occur whenin some specialΩ(see [5]–[8]). When n ≥3, Winker[9]showed that there exists radially symmetric solution blowing up in finite time with proper initial conditions.
In numerous biological processes, general mechanisms in cell include not only attractive but also repulsive signals, which can form various interesting biological patterns (see [10]).Then the model can be expressed as following attraction-repulsion chemotaxis system:
The system (1.3) is proposed by [11] to describe the aggregation of microglia observed in Alzheimer’s disease. Fewer blow-up results are available for system (1.3) than (1.1),because (1.3) relies on Lyapunov function. When n = 1, τ = 1, global existence, non-trivial stationary, asymptotic behavior and pattern formation of solutions to the system (1.3) have been studied in [12]–[13]; when n = 2, τ = 1, if β≠ δ and repulsion prevails over attraction(i.e., ξγ −χα > 0), then the system (1.3) admits a unique global bounded solution (see [14]);in the case τ ≡0, Yuet al.[15]proved that the finite time blow-up for the nonradial solution happens when
when δ ≥ β, or
if δ < β. For more detail results on attraction-repulsion chemotaxis system, we refer the readers to [17]–[20]. Blow-up is an extremely behavior. In order to restrain the behavior,people add the logistic source. More detail results on attraction-repulsion chemotaxis system with the logistic source, the readers can see [21]–[24].
Inspired by above papers, this paper mainly aims to understand the competition among the repulsion, the attraction, the nonlinear productions. Precisely, we consider the global boundedness and the finite time blow-up of solutions to the following parabolic-ellipticelliptic attraction-repulsion chemotaxis system:
where u = u(x, t) denotes the density of cells, v = v(x, t) represents the concentration of the chemoattractant, w = w(x, t) is a secondary chemical signal as a chemorepellent which mediates the cell’s chemotactic response to the chemoattractant v.Ωis a bounded domain in R2with smooth boundary ∂Ω,denotes the derivative with respect to the outer normal.χ, ξ > 0, α, β, γ, δ > 0, q ≥1, r ≥1 and the nonnegative initial data u0(x) ∈C0(). In this model, the behavior of solutions relies on the interaction between the attraction and repulsion, with nonlinear productions.
The main results of this paper read as follows:
Theorem 1.1(i)Ifq < r,then the system(1.4)has a unique nonnegative and globally bounded solution;
(ii)Ifq = randχα − ξγ < 0,then the solution of(1.4)is globally bounded.
Theorem 1.2Let Ω∈R2be a smooth bounded domain andx0∈Ω. Assume thatis small enough. Then if either of the following case holds:
(i) q = r, χα − ξγ > 0,and
(ii) q > r, χαq − ξγr > 0,the solution of(1.4)blows up in finite time.
This paper is structured as follows. In Section 2, we collect some preliminaries which are used later. Section 3 is devoted to proving Theorem 1.1. Finally, we give some blow-up conditions for the system (1.4), and prove Theorem 1.2 in Section 4.
In this section, we collect some classical conclusions as preliminaries. We begin with the local existence of solutions to (1.4).
Lemma 2.1[7],[15],[16]Assume thatu0(x) ∈C0()is nonnegative in Ω. Then there exists a unique triple(u, v, w)of nonnegative functions fromC0(Ω× (0, Tmax)) ∩C2,1(Ω×(0, Tmax))withTmax∈(0, ∞]solving(1.4)in the classical sense. Furthermore,ifTmax< ∞,then
Lemma 2.2[7],[15],[16]Letube the solution of
whereB := {x ∈R2| |x| < R}andf ∈Lp(B), 1 ≤p ≤ ∞. Then
whereG(x, y)is the green function of−∆onBwith homogeneous Dirichlet boundary condition. Besides, G(x, y)satisfies the following properties:
(i) G(x, y) = N(x−y)+K(x, y),whereN(x−y) = −log |x−y|andK ∈C2(B ×B);
(ii) G(x, y) = G(y, x)forx, y ∈;
(iii) |∇xG(x, y)| ≤onB × Bfor someC > 0.
Lemma 2.3[7],[15],[16]Letu ∈C2()satisfy
withf ∈C0(¯Ω), ρ > 0. Then there exist positive constantsCmandCnsuch that
We define the functionϕ ∈C1([0, ∞)) ∩W2,∞((0, ∞))withr2> r1> 0by
where
Lemma 2.4[7],[15],[16]We construct Φ(x) := ϕ(|x|) ∈C1(R2) ∩W2,∞(R2),which satisfies the following
and
Moreover
whereBi:= {x ∈R2| |x| < ri}withR, ri> 0, i = 1, 2, 3, 4.
Lemma 3.1[22]Let(u, v, w)be a nonnegative local solution to(1.4)ensured by Lemma2.1. Then for anyη > 0, θ > 1,there isc1= c1(η, θ) > 0such that
and
Proof.We integrate the first equation of (1.4) with respect to x ∈Ωand obtain
so
The second equation of (1.4) implies
Multiply the second equation of (1.4) by vθ−1, then integrate overΩand by Young’s inequality, we get
Then we can know that
In view of Ehrling’s lemma, for any η > 0, θ > 1, there exists a c2= c2(η, θ) > 0 such that
with c3= c3(η, θ) > 0. Since 1 ≤q ≤qθ, by the interpolation inequality, the Young’s inequality and (3.3), we have
Similarly, (3.2) can be obtained by the same procedure as above. This completes the proof.
Proof of Theorem 1.1We begin with showing that for any p > 1, there exists a c = c(p) > 0 such that
Multiply the first equation of (1.4) by up−1and then integrate overΩ, we obtain that
By Young’s inequality with (3.2) and η > 0, we have
where c5= c5(p, η) > 0, c6= c6(p, η) > 0. Hence
Case 1. Let q < r, by Young’s inequality, we have
with c7= c7(p) > 0. We know from (3.11) and (3.12) that
where c8= c6+ c7. We let η =, hence
Due to Young’s inequality, there is a c9= c9(p) > 0 such that
From (3.13) and (3.14), we obtain
with c10= c8+ c9. This implies (3.9).
Case 2. If q = r, we know from (3.11) that
If χα − ξγ < 0, taking η => 0, we have that
By Young’s inequality, there exists c11= c11(p) > 0,
We get from (3.15) and (3.16) that
with c12= c6+ c11. This implies (3.9).
Now, we show that
with some C > 0, which concludes Tmax= ∞by Lemma 2.1.
Case 1. Let p0> max{rn, 1}. Applying an elliptic Lpestimate to the third equation in(1.4) we get from (3.9) that
with C0> 0. Then by the Sobolev imbedding theorem with c0> 0, we have that
We get from (3.10) and (3.18) that
Case 2. Let q < r. By Young’s inequality, we have that
Combining (3.19)–(3.21), we have that
and then
For any t ∈(0, Tmax), we have that
and thus (3.17) is obtained.
Let q = r, (3.19) becomes that
By Young’s inequality and χα − ξγ < 0, we know that
From (3.22) and (3.33), we can obtain that
and hence
Obviously,
Thus (3.17) is obtained.
The proof of Theorem 1.1 is completed.
Let (u, v, w) be the local solution of (1.4) ensured by Lemma 2.1. We should show Tmax<∞. It suffices to find a T > 0 such that theΦ-weighted integral of u(x, t) tends to zeros as t →T. Inspired by [7], [15], [16], this is realized by the following propositions.
Proposition 4.1Letq = r, x0∈Ω and0 < r1< r2< dist(x0, ∂Ω),wheredist(x0, ∂Ω)denotes the distance betweenx0and∂Ω. Then there existC1, C2> 0relying onr1, r2,dist(x0, ∂Ω)such that fort ∈(0, Tmax),
where Φ(x) = ϕ(|x|)defined by Lemma2.1.
Proof.We proceed somewhat similarly to [7] and [16]. Without loss of generality, we suppose that x0is the origin. Multiply the first equation of (1.4) byΦ(x) and integrate overΩ. Since the Neumann boundary condition of (1.4),with r2< dist(x0, ∂Ω) by Lemma 2.4, we know that
By ∆Φ ≤4 onΩ(see (2.3) and (2.4) ) andu0(x)dx, one has
Take r3, r4> 0 such that 0 < r2< r3< r4< dist(x0, ∂Ω) and define ζ ∈(R2) with 0 ≤ ζ ≤1 satisfying
and h(x, t) := ζ(x)v(x, t). By the second equation of (1.4), it is easy that we can verify that h(x, t) satisfies
for t ∈(0, Tmax), where g := −2∇ζ · ∇v − ∆ζv. By Lemma 2.2, h(x, t) can be expressed as follows
Since ∇Φ≡0 outside of B2by Lemma 2.4 and h ≡v in B3, we can obtain that
In the following we firstly estimate on I. Since Lemma 2.2(i) with ζ = 1 in B3,
Because of the symmetry property of integrals and ∇Φ≡0 outside B2, we get from the estimate (2.5), (2.6) andΦ≥outside B1that
and
and
So
According to Lemma 2.2(ii), I3can be expressed as follows:
Thus we obtain the estimate
Now, we estimate II. Since g := −2∇ζ · ∇v − △ζv in B3, we obtain by Lemma 2.2(iii)and the H¨older’s inequality that
with C3, C4> 0.
To calculate further, we apply Lemma 2.3 to the third equation of (1.4) to get
with C5is a positive constant. Then
where C6is a constant depending on ∥∇ζ∥L∞, ∥△ζ∥L∞and C5. Hence
Estimating III, letting ψ(x, t) :=, we have that
Noticing |∇xG(x −y)| ≤C7|x −y| and using the H¨older’s inequality, we obtain that
with C7> 0. Here, we use
Applying Lemma 2.3 to the third equation of (1.4), we have that
with C8> 0. Hence
where C9= C7C8. Thus
with C10> 0.
Combining the estimating I, II, III, we can obtain
Combining (4.2) with (4.3) and (4.4), we obtain that
If χα − ξγ > 0, we have that
Combining (4.5) and (4.6), this completes the proof.
Lemma 4.1Let Ω∈R2be a smooth bounded domain andx0∈Ω. Assume thatis sufficiently small, q = r, χα − ξγ > 0,and
Then the solution of(1.4)blows up in finite time.
Proof.Denote
We define
By the definition ofΦ(x) with Lemma 2.3 associated, we know
Together with the condition in Theorem 1.2(i), it is easy to find that both E(0) < 0 and E′(s) > 0 holds for s > 0. This yields E(MΦ(0)) < 0 providedsmall enough. Combining with (4.7) to get
We obtain from (4.7) and (4.8) that
This concludes that there exists a T ∈(0, ∞) such that MΦ(t)→0 as t →T. We complete the proof.
Proposition 4.2Letq > r, x0∈Ω and0 < r1< r2< dist(x0, ∂Ω)denote the distance betweenx0and∂Ω. Then there existC11, C12> 0relying onr1, r2, dist(x0, ∂Ω),such that fort ∈(0, Tmax),
Proof.From (4.2), we have that
We have from (4.3) that
By the H¨older’s inequality, one has
So, we can obtain from (4.4) and (4.12) that
By the similar proof of (4.6), if χαq − ξγr > 0, we can obtain that
Combining (4.8), (4.11), (4.13) and (4.14), we complete the proof.
Lemma 4.2Let Ω∈R2be a smooth bounded domain andx0∈Ω. Assume that is sufficiently small, q > r, χαq − ξγr > 0,
Then the solution of(1.4)blows up in finite time.
Proof.By the similar proof of Lemma 4.1, we can get the result of Lemma 4.2, and skip the proof for conciseness.
The proof of Theorem 1.2 is completed by Lemmas 4.1 and 4.2.
Communications in Mathematical Research2019年4期