SUN Yuan-yuan
(Department of Public,Guangzhou Huaxia Technical College,Guangzhou 510900,China)
Vertex Algebra Sheaf Structure on Torus
SUN Yuan-yuan
(Department of Public,Guangzhou Huaxia Technical College,Guangzhou 510900,China)
In this paper,we first give a 1-1 corresponds between torus C/Λ and cubic curve C inAs complex manifold,they are isomorphic,therefore we can treat C/Λ as a variety and construction a vertex algebra sheaf on it.
torus;vertex algebra;sheaf
2000 MR Subject Classification:14A99,17B69
Article ID:1002—0462(2016)01—0044—07
Chin.Quart.J.of Math.
2016,31(1):44—50
Vertex algebras have been studied by mathematicians for more than a decade,but still very little is known about the general structure of vertex algebra.H Li[10]B Feigin and E Frenkel[6],I Frenkel and Y Zhu[11]give some examples respectively.Vadim Schechtman[2]proved that we can define certain sheaves of vertex algebras on smooth manifolds in 1999.As an example,we construct a vertex algebra sheaf structure on torus.
To prepare for our work,we begin in section 2 by reviewing the basic concepts of torus and Heisenberg vertex algebra.In section 3,we construct a vertex algebra sheaf on torus.
2.1 Torus
We will define torus as C/Λ,which Λ≡{mω1+nω2|m,n∈Z}≡((ω1,ω2))is a lattice.(ω1,ω2∈C and linear independent).It is not difficult to prove that C/Λ isomorphic to C⊂, which is a cubic curve.
C is a variety and C is also a scheme.Projective subschema inalways are ProjC[x0,x1,x2] /I,where I is a homogeneous ideal.So we have C=ProjC[b1,b2,b3](f),f=(b3)2b1-c3(b2)3-c2(b2)2b1-c1b2(b1)2-c0(b1)3,it means C/Λ~=C=ProjC[b1,b2,b3]/(f).Now,we can define our vertex algebra sheaf on C/Λ.
2.2 Heisenberg Vertex Algebra
all other brackets being zero.
As an H3-module,V3=〈1〉,subject to the relations:
Let us define the structure of a conformal vertex algebra on V3.
•(Vacuum Vector)1;
•(Translation Operator)L-11=0,[L-1,an]=-nan-1,[L-1,bn]=-(n-1)bn-1;
•(Vertex Operators)
•(Locality)
•(Conformal Structure)Conformal vector
Virasoro field
In other words,vertex algebra V3is generated by the even fields bi(z),aj(z)of conformal weights 0 and 1 respectively,subject to the relations above.
We know C=ProjC[b1,b2,b3]/(f)and the equation of cubic curve C is f=(b3)2b1-c3(b2)3-c2(b2)2b1-c1b2(b1)2-c0(b1)3.Let A3=C[b1,b2,b3]/(f),then we haveProj(A3).So we get V3is A3-module.
Proposition 1Define vertex algebra sheaf on torus.
Proof
Step 1In the Zariski topology,open sets on C/Λ are Distinguished open subsets.We choose three open subsets as the base
The three forming topological base
And,
Step 2We define structure of vertex algebras on the Distinguished open subsets,i.e.,define V3;bi,i=1,2,3 are vertex algebras.
We are going to introduce a structure of a conformal vertex algebra on the spaceLet us define the map
We have
•(Vertex Operators)Because V3is conformal vertex algebra,we just need check
is well defined.
Choose a formal power serieswe prove thatis an element in
First,we have
Let us define by the Taylor formula
On the other hand,
There exists only a finite number of tuples(k1,···,kI)satisfying(3.3)and(3.4).Therefore,are well defined endomorphisms of
So,
All ki≠0.Let I+(I-)be the number of positive(negative)ki.We haveM-k,hencetherefore,I≤2M-k. Therefore,when(3.5)action on the element v,only a finite number of terms in the sun over(i1,i2,i3)survives.Therefore,(3.5)is a well defined element of End
•(Locality)
•(Conformal Structure)We can get it from the map(3.1).
Next,we construct a structure of a conformal vertex algebra on the space V3;b1.
Since V3;b1=A3;b1⊗A3V3,therefore,the vacuum vector,translation operator,conformal structure of V3;b1are similar to
•(Vertex Operators)
(b1(z))-1=(b0+b1(z)+b1z-1+···)-1
The coefficient of z0istherefore the coefficient at each power of z is an infinite sum,but as an operator acting on V3;b1,it is well defined since only finite number of terms act nontrivially.
We know
For any v∈V and large enough j,we have Aj·v=0.In other words A(z)·v∈V((z)).
By the above(3.6),we can give the general field
•(Locality)We have[bn,bm]=0,then we get
Therefore,we completed the structure of a conformal vertex algebra on the space V3;b1.Then, sectionis also a conformal vertex algebra,this Proposition provides a structure of a conformal vertex algebra on sectionand section Γ
Step 3Section which corresponding to any open set are all vertex algebra.For any open set U⊂X,we define
which W ⊂V⊂U and V,W ∈B.The element of Γcan be regard as limit of the element which belongs to Γand their vacuum vector,translation operator,vertex operator are the same.Then we get Γis also a vertex algebra.
Step 4Define the restriction map.∀U,V⊂X and U⊂V,we have known that bothandare vertex algebras.Therefore,the restriction map is a morphism of vertex algebras.By[9]andare satisfy the morphism of vertex algebras.
Obviously,we have
(2)For all open set,U,ρUUis identity map;
Then,we construct a presheaf.
then we glue the two open subsets together.
Now,we complete the structure of vertex algebra sheafon torus C/Λ.
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O187.1,O412.3Document code:A
date:2015-09-10
Supported by the National Natural Science Foundation of China(11475178,11571119)
Biography:SUN Yuan-yuan(1983-),female,native of Jiaozuo,Henan,a lecturer of Guangzhou Huaxia Technical College,M.S.D.,engages in mathematical physics.
Chinese Quarterly Journal of Mathematics2016年1期